Start of QuestionsA rectangular field is eleven times as long as it is wide. If the perimeter of the field is 1560 feet, what are the dimensions of the field?A) Write an equation you can use to answer the given question. Let ww be the width of the field. Do not solve the equation yet.The equation is syntax error: this is not an equation (Make sure you use the correct variable.)B) Use your equation to find the dimensions of the field.The width of the field is feet.The length of the field is feet.

Answer:A. [tex]24w=1,560[/tex]B. [tex]\text{Width}=w=65\ feet\\ \\\text{Length}=11w=715\ feet[/tex]Step-by-step explanation:Let w feet be the width of the field. A rectangular field is eleven times as long as it is wide, then the length of the field is 11w feet.A. The perimeter of the field is[tex]\text{Perimeter}=2(\text{Widht}+\text{Length})\\ \\\text{Perimeter}=2(w+11w)=2\cdot 12w=24w[/tex]If the perimeter of the field is 1,560 feet, then[tex]24w=1,560[/tex]B. Solve this equation:[tex]w=\dfrac{1,560}{24}\\ \\\text{Width}=w=65\ feet\\ \\\text{Length}=11w=715\ feet[/tex]